求大神帮忙改代码C++！！！在线等！！！把Student类中的num name sex移植到Teacher类中

#include <iostream>
using namespace std;

class Teacher
{
private:
int num;
char name[20];
char sex;
float pay;
public:
Teacher();
Teacher(Student &); //语法错误 标识符"Student" error C2535: “Teacher::Teacher(void)”: 已经定义或声明成员函数
Teacher(int n, char nam[],char s,float p);
void display(){cout<<"num:"<<num<<endl<<"name:"<<name<<endl<<"sex:"<<sex<<endl<<"pay:"<<pay<<endl;}
};

class Student
{
private:
int num;
char name[20];
char sex;
float score;
public:
Student(int ,char[],char,float);
friend Teacher;
void display()
{cout<<"num:"<<num<<endl<<"name:"<<name<<endl<<"sex:"<<sex<<endl<<"score:"<<score<<endl;}
};

Teacher::Teacher(Student &s) //未声明标识符's' 未声明标识符‘Student’
{ // error C2448: “Teacher::{ctor}”: 函数样式初始值设定项类似函数定义
num=s.num;
strcpy(name,s.name);
sex=s.sex;
}

Teacher::Teacher(int n, char nam[], char s,float p)
{
num=n;
strcpy(name,nam);
sex=s;
pay=p;
}

Student::Student(int n,char nam[],char s,float sco)
{
num=n;
strcpy(name,nam);
sex=s;
score=sco;
}

int main()
{
Student s1(100101,"zhang",'m',20.5);
Teacher t1;
t1=Teacher(s1); // error C2440: “<function-style-cast>”: 无法从“Student”转换为“Teacher”
t1.display();
return 0;
}

1、使用Student类需要前向声明，即在Teacher类定义前加class Student;的声明；

2、Teacher（Student&)这不属于复制构造函数，不是编译器能自动调用的，要自己定义；
3、所以主函数中Teacher t1;是无定义的，因为Teacher无默认构造函数；
4、可以直接调用Teacher（Student&);Teacher t1(s1);
最后，teaxcher的pay成员将丢失。
建议，最好用类继承方法：先声明Person类，再声明class Teacher:public Person; class Student:public Person...有兴趣可试一试。
补充一点：不建议使用字符串，而应使用string类，在复制、赋值时避免出错。

这个和不简单 自己想

1.在Teacher类中使用了Student的对象，需要先在Teacher类之前定义Student类 class Student; class Teacher { 2.在main函数中使用Teacher的构造，需要直接传入对象，否则就是使用无参数的构造函数 Teacher t1(s1); 代码如下： #include <iostream> using namespace std; class Student; class Teacher { private: int num; char name[20]; char sex; float pay; public: Teacher(); Teacher(Student &); //语法错误 标识符"Student" error C2535: “Teacher::Teacher(void)”: 已经定义或声明成员函数 Teacher(int n, char nam[],char s,float p); void display(){cout<<"num:"<<num<<endl<<"name:"<<name<<endl<<"sex:"<<sex<<endl<<"pay:"<<pay<<endl;} }; class Student { private: int num; char name[20]; char sex; float score; public: Student(int ,char[],char,float); friend Teacher; void display() {cout<<"num:"<<num<<endl<<"name:"<<name<<endl<<"sex:"<<sex<<endl<<"score:"<<score<<endl;} }; Teacher::Teacher(Student &s) //未声明标识符's' 未声明标识符‘Student’ { // error C2448: “Teacher::{ctor}”: 函数样式初始值设定项类似函数定义 num=s.num; strcpy(name,s.name); sex=s.sex; } Teacher::Teacher(int n, char nam[], char s,float p) { num=n; strcpy(name,nam); sex=s; pay=p; } Student::Student(int n,char nam[],char s,float sco) { num=n; strcpy(name,nam); sex=s; score=sco; } int main() { Student s1(100101,"zhang",'m',20.5); Teacher t1(s1); //t1=Teacher(s1); // error C2440: “<function-style-cast>”: 无法从“Student”转换为“Teacher” t1.display(); return 0; } 问题解决，请采纳！

1.在teacher类中使用了student的对象，需要先在teacher类之前定义student类 class student; class teacher { 2.在main函数中使用teacher的构造，需要直接传入对象，否则就是使用无参数的构造函数 teacher t1(s1); 代码如下： #include <iostream> using namespace std; class student; class teacher { private: int num; char name[20]; char sex; float pay; public: teacher(); teacher(student &); //语法错误 标识符"student" error c2535: “teacher::teacher(void)”: 已经定义或声明成员函数 teacher(int n, char nam[],char s,float p); void display(){cout<<"num:"<<num<<endl<<"name:"<<name<<endl<<"sex:"<<sex<<endl<<"pay:"<<pay<<endl;} }; class student { private: int num; char name[20]; char sex; float score; public: student(int ,char[],char,float); friend teacher; void display() {cout<<"num:"<<num<<endl<<"name:"<<name<<endl<<"sex:"<<sex<<endl<<"score:"<<score<<endl;} }; teacher::teacher(student &s) //未声明标识符&apos;s&apos; 未声明标识符‘student’ { // error c2448: “teacher::{ctor}”: 函数样式初始值设定项类似函数定义 num=s.num; strcpy(name,s.name); sex=s.sex; } teacher::teacher(int n, char nam[], char s,float p) { num=n; strcpy(name,nam); sex=s; pay=p; } student::student(int n,char nam[],char s,float sco) { num=n; strcpy(name,nam); sex=s; score=sco; } int main() { student s1(100101,"zhang",&apos;m&apos;,20.5); teacher t1(s1); //t1=teacher(s1); // error c2440: “<function-style-cast>”: 无法从“student”转换为“teacher” t1.display(); return 0; } 问题解决，请采纳！

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